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13000211141 = 19684221639
BaseRepresentation
bin11000001101101111…
…10111101011000101
31020120000012011002112
430012313313223011
5203111023224031
65545555350405
7640104654131
oct140667675305
936500164075
1013000211141
11557130a055
1226298b2405
1312c2446b38
148b47c23c1
1551149462b
hex306df7ac5

13000211141 has 4 divisors (see below), whose sum is σ = 13684432800. Its totient is φ = 12315989484.

The previous prime is 13000211131. The next prime is 13000211177. The reversal of 13000211141 is 14111200031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13000211141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000211101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342110801 + ... + 342110838.

It is an arithmetic number, because the mean of its divisors is an integer number (3421108200).

Almost surely, 213000211141 is an apocalyptic number.

It is an amenable number.

13000211141 is a deficient number, since it is larger than the sum of its proper divisors (684221659).

13000211141 is an equidigital number, since it uses as much as digits as its factorization.

13000211141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 684221658.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 13000211141 its reverse (14111200031), we get a palindrome (27111411172).

The spelling of 13000211141 in words is "thirteen billion, two hundred eleven thousand, one hundred forty-one".

Divisors: 1 19 684221639 13000211141