Base | Representation |
---|---|
bin | 1011110100101101100100… |
… | …0010010111100100111111 |
3 | 1201000210211011000012220221 |
4 | 2331023121002113210333 |
5 | 3200443413323030211 |
6 | 43352114243122211 |
7 | 2511143244265036 |
oct | 275133102274477 |
9 | 51023734005827 |
10 | 13000212314431 |
11 | 41623a4a33771 |
12 | 155b640973367 |
13 | 733bb7964864 |
14 | 32d2dc2d171d |
15 | 178273124c71 |
hex | bd2d909793f |
13000212314431 has 2 divisors, whose sum is σ = 13000212314432. Its totient is φ = 13000212314430.
The previous prime is 13000212314417. The next prime is 13000212314437. The reversal of 13000212314431 is 13441321200031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13000212314431 - 223 = 13000203925823 is a prime.
It is a super-2 number, since 2×130002123144312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13000212314396 and 13000212314405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13000212314437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500106157215 + 6500106157216.
It is an arithmetic number, because the mean of its divisors is an integer number (6500106157216).
Almost surely, 213000212314431 is an apocalyptic number.
13000212314431 is a deficient number, since it is larger than the sum of its proper divisors (1).
13000212314431 is an equidigital number, since it uses as much as digits as its factorization.
13000212314431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13000212314431 its reverse (13441321200031), we get a palindrome (26441533514462).
The spelling of 13000212314431 in words is "thirteen trillion, two hundred twelve million, three hundred fourteen thousand, four hundred thirty-one".
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