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13000212314431 is a prime number
BaseRepresentation
bin1011110100101101100100…
…0010010111100100111111
31201000210211011000012220221
42331023121002113210333
53200443413323030211
643352114243122211
72511143244265036
oct275133102274477
951023734005827
1013000212314431
1141623a4a33771
12155b640973367
13733bb7964864
1432d2dc2d171d
15178273124c71
hexbd2d909793f

13000212314431 has 2 divisors, whose sum is σ = 13000212314432. Its totient is φ = 13000212314430.

The previous prime is 13000212314417. The next prime is 13000212314437. The reversal of 13000212314431 is 13441321200031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13000212314431 - 223 = 13000203925823 is a prime.

It is a super-2 number, since 2×130002123144312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13000212314396 and 13000212314405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000212314437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500106157215 + 6500106157216.

It is an arithmetic number, because the mean of its divisors is an integer number (6500106157216).

Almost surely, 213000212314431 is an apocalyptic number.

13000212314431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000212314431 is an equidigital number, since it uses as much as digits as its factorization.

13000212314431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13000212314431 its reverse (13441321200031), we get a palindrome (26441533514462).

The spelling of 13000212314431 in words is "thirteen trillion, two hundred twelve million, three hundred fourteen thousand, four hundred thirty-one".