Search a number
-
+
130002131203277 is a prime number
BaseRepresentation
bin11101100011110001111010…
…110110011011010011001101
3122001022002020001020122001112
4131203301322312123103031
5114014423331042001102
61140254053221021405
736245226000505214
oct3543617266332315
9561262201218045
10130002131203277
1138471659a08853
12126b734a854865
1357701c0c79908
1424161cb24c07b
1510069c1726252
hex763c7ad9b4cd

130002131203277 has 2 divisors, whose sum is σ = 130002131203278. Its totient is φ = 130002131203276.

The previous prime is 130002131203267. The next prime is 130002131203313. The reversal of 130002131203277 is 772302131200031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111708538239076 + 18293592964201 = 10569226^2 + 4277101^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130002131203277 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130002131203247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65001065601638 + 65001065601639.

It is an arithmetic number, because the mean of its divisors is an integer number (65001065601639).

Almost surely, 2130002131203277 is an apocalyptic number.

It is an amenable number.

130002131203277 is a deficient number, since it is larger than the sum of its proper divisors (1).

130002131203277 is an equidigital number, since it uses as much as digits as its factorization.

130002131203277 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10584, while the sum is 32.

The spelling of 130002131203277 in words is "one hundred thirty trillion, two billion, one hundred thirty-one million, two hundred three thousand, two hundred seventy-seven".