Base | Representation |
---|---|
bin | 10010111010101111010… |
… | …011101111101011011111 |
3 | 11121021120201110020002202 |
4 | 102322233103233223133 |
5 | 132244420423442343 |
6 | 2433115504242115 |
7 | 162631511554214 |
oct | 22725723575337 |
9 | 4537521406082 |
10 | 1300021312223 |
11 | 4613771593a7 |
12 | 18bb5261033b |
13 | 9578c649c1a |
14 | 46cc8335b0b |
15 | 23c3ac34db8 |
hex | 12eaf4efadf |
1300021312223 has 2 divisors, whose sum is σ = 1300021312224. Its totient is φ = 1300021312222.
The previous prime is 1300021312199. The next prime is 1300021312231. The reversal of 1300021312223 is 3222131200031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1300021312223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1300021312195 and 1300021312204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300021312243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650010656111 + 650010656112.
It is an arithmetic number, because the mean of its divisors is an integer number (650010656112).
Almost surely, 21300021312223 is an apocalyptic number.
1300021312223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300021312223 is an equidigital number, since it uses as much as digits as its factorization.
1300021312223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1300021312223 its reverse (3222131200031), we get a palindrome (4522152512254).
The spelling of 1300021312223 in words is "one trillion, three hundred billion, twenty-one million, three hundred twelve thousand, two hundred twenty-three".
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