13000248949 has 2 divisors, whose sum is σ = 13000248950. Its totient is φ = 13000248948.

The previous prime is 13000248929. The next prime is 13000248967. The reversal of 13000248949 is 94984200031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11423761924 + 1576487025 = 106882^2 + 39705^2 .

It is a cyclic number.

It is not a de Polignac number, because 13000248949 - 2⁵ = 13000248917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000248929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500124474 + 6500124475.

It is an arithmetic number, because the mean of its divisors is an integer number (6500124475).

Almost surely, 2^13000248949 is an apocalyptic number.

It is an amenable number.

13000248949 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000248949 is an equidigital number, since it uses as much as digits as its factorization.

13000248949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 40.

The spelling of 13000248949 in words is "thirteen billion, two hundred forty-eight thousand, nine hundred forty-nine".