130003001312022 has 24 divisors (see below), whose sum is σ = 282342226935600. Its totient is φ = 43231401858960.

The previous prime is 130003001311957. The next prime is 130003001312027. The reversal of 130003001312022 is 220213100300031.

130003001312022 is a `hidden beast` number, since 1 + 30 + 0 + 0 + 300 + 1 + 312 + 0 + 22 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 130003001311986 and 130003001312004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130003001312027) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8577651522 + ... + 8577666677.

It is an arithmetic number, because the mean of its divisors is an integer number (11764259455650).

Almost surely, 2^{130003001312022} is an apocalyptic number.

130003001312022 is an abundant number, since it is smaller than the sum of its proper divisors (152339225623578).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130003001312022 is a wasteful number, since it uses less digits than its factorization.

130003001312022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17155318628 (or 17155318625 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 130003001312022 its reverse (220213100300031), we get a palindrome (350216101612053).

The spelling of 130003001312022 in words is "one hundred thirty trillion, three billion, one million, three hundred twelve thousand, twenty-two".