Base | Representation |
---|---|
bin | 1011110100101101111001… |
… | …1001101101111000111101 |
3 | 1201000211001102101001000110 |
4 | 2331023132121231320331 |
5 | 3200444104343234323 |
6 | 43352131220220233 |
7 | 2511145416316344 |
oct | 275133631557075 |
9 | 51024042331013 |
10 | 13000302321213 |
11 | 416244081a139 |
12 | 155b666b3a679 |
13 | 733c004b98cc |
14 | 32d30a240b5b |
15 | 17827aea3793 |
hex | bd2de66de3d |
13000302321213 has 4 divisors (see below), whose sum is σ = 17333736428288. Its totient is φ = 8666868214140.
The previous prime is 13000302321137. The next prime is 13000302321229. The reversal of 13000302321213 is 31212320300031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13000302321213 - 221 = 13000300224061 is a prime.
It is a super-2 number, since 2×130003023212132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13000302321213.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13000302321113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2166717053533 + ... + 2166717053538.
It is an arithmetic number, because the mean of its divisors is an integer number (4333434107072).
Almost surely, 213000302321213 is an apocalyptic number.
It is an amenable number.
13000302321213 is a deficient number, since it is larger than the sum of its proper divisors (4333434107075).
13000302321213 is an equidigital number, since it uses as much as digits as its factorization.
13000302321213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4333434107074.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 13000302321213 its reverse (31212320300031), we get a palindrome (44212622621244).
The spelling of 13000302321213 in words is "thirteen trillion, three hundred two million, three hundred twenty-one thousand, two hundred thirteen".
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