Base | Representation |
---|---|
bin | 1011110100101101111011… |
… | …0111110110010011011111 |
3 | 1201000211001222020100010002 |
4 | 2331023132313312103133 |
5 | 3200444113404014444 |
6 | 43352132101404515 |
7 | 2511145543415024 |
oct | 275133667662337 |
9 | 51024058210102 |
10 | 13000310219999 |
11 | 4162445224663 |
12 | 155b66970973b |
13 | 733c02023c4b |
14 | 32d30b2d954b |
15 | 17827ba13d4e |
hex | bd2dedf64df |
13000310219999 has 4 divisors (see below), whose sum is σ = 13001625651336. Its totient is φ = 12998994788664.
The previous prime is 13000310219983. The next prime is 13000310220031. The reversal of 13000310219999 is 99991201300031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13000310219999 - 24 = 13000310219983 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13000310219909) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 657700844 + ... + 657720609.
It is an arithmetic number, because the mean of its divisors is an integer number (3250406412834).
Almost surely, 213000310219999 is an apocalyptic number.
13000310219999 is a deficient number, since it is larger than the sum of its proper divisors (1315431337).
13000310219999 is an equidigital number, since it uses as much as digits as its factorization.
13000310219999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1315431336.
The product of its (nonzero) digits is 118098, while the sum is 47.
The spelling of 13000310219999 in words is "thirteen trillion, three hundred ten million, two hundred nineteen thousand, nine hundred ninety-nine".
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