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1300033011073 is a prime number
BaseRepresentation
bin10010111010110000000…
…000010111110110000001
311121021121112110120220111
4102322300000113312001
5132244431422323243
62433121003111321
7162632013160516
oct22726000276601
94537545416814
101300033011073
11461382819975
1218bb56512541
1395791bb4b14
1446cc9add30d
1523c3bc9639d
hex12eb0017d81

1300033011073 has 2 divisors, whose sum is σ = 1300033011074. Its totient is φ = 1300033011072.

The previous prime is 1300033011019. The next prime is 1300033011149. The reversal of 1300033011073 is 3701103300031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 714391777089 + 585641233984 = 845217^2 + 765272^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300033011073 - 213 = 1300033002881 is a prime.

It is a super-2 number, since 2×13000330110732 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1300033011373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650016505536 + 650016505537.

It is an arithmetic number, because the mean of its divisors is an integer number (650016505537).

Almost surely, 21300033011073 is an apocalyptic number.

It is an amenable number.

1300033011073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300033011073 is an equidigital number, since it uses as much as digits as its factorization.

1300033011073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 567, while the sum is 22.

The spelling of 1300033011073 in words is "one trillion, three hundred billion, thirty-three million, eleven thousand, seventy-three".