Base | Representation |
---|---|
bin | 111100100010011001… |
… | …1010001010110110010 |
3 | 110102120011011102002111 |
4 | 1321010303101112302 |
5 | 4112221321410002 |
6 | 135420034035534 |
7 | 12251413621336 |
oct | 1710463212662 |
9 | 412504142074 |
10 | 130003310002 |
11 | 5015252aa75 |
12 | 21241a18baa |
13 | c34a793307 |
14 | 6413acb7c6 |
15 | 35ad2b93d7 |
hex | 1e44cd15b2 |
130003310002 has 4 divisors (see below), whose sum is σ = 195004965006. Its totient is φ = 65001655000.
The previous prime is 130003309921. The next prime is 130003310111. The reversal of 130003310002 is 200013300031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 200013300031 = 4733 ⋅42259307.
It can be written as a sum of positive squares in only one way, i.e., 90624479521 + 39378830481 = 301039^2 + 198441^2 .
It is a super-2 number, since 2×1300033100022 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32500827499 + ... + 32500827502.
Almost surely, 2130003310002 is an apocalyptic number.
130003310002 is a deficient number, since it is larger than the sum of its proper divisors (65001655004).
130003310002 is an equidigital number, since it uses as much as digits as its factorization.
130003310002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65001655003.
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 130003310002 its reverse (200013300031), we get a palindrome (330016610033).
The spelling of 130003310002 in words is "one hundred thirty billion, three million, three hundred ten thousand, two".
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