130003332312121 has 4 divisors (see below), whose sum is σ = 130030343190052. Its totient is φ = 129976321434192.

The previous prime is 130003332312097. The next prime is 130003332312151. The reversal of 130003332312121 is 121213233300031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 76052544497721 + 53950787814400 = 8720811^2 + 7345120^2 .

It is a cyclic number.

It is not a de Polignac number, because 130003332312121 - 2⁵ = 130003332312089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130003332312151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13505431746 + ... + 13505441371.

It is an arithmetic number, because the mean of its divisors is an integer number (32507585797513).

Almost surely, 2^{130003332312121} is an apocalyptic number.

It is an amenable number.

130003332312121 is a deficient number, since it is larger than the sum of its proper divisors (27010877931).

130003332312121 is an equidigital number, since it uses as much as digits as its factorization.

130003332312121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27010877930.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 130003332312121 its reverse (121213233300031), we get a palindrome (251216565612152).

The spelling of 130003332312121 in words is "one hundred thirty trillion, three billion, three hundred thirty-two million, three hundred twelve thousand, one hundred twenty-one".