13000344002233 has 8 divisors (see below), whose sum is σ = 15259091029952. Its totient is φ = 10841985731376.

The previous prime is 13000344002203. The next prime is 13000344002237. The reversal of 13000344002233 is 33220044300031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13000344002233 - 2¹⁷ = 13000343871161 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13000344002198 and 13000344002207.

It is not an unprimeable number, because it can be changed into a prime (13000344002237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25097188935 + ... + 25097189452.

It is an arithmetic number, because the mean of its divisors is an integer number (1907386378744).

Almost surely, 2^{13000344002233} is an apocalyptic number.

It is an amenable number.

13000344002233 is a deficient number, since it is larger than the sum of its proper divisors (2258747027719).

13000344002233 is an equidigital number, since it uses as much as digits as its factorization.

13000344002233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50194378431.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 13000344002233 its reverse (33220044300031), we get a palindrome (46220388302264).

The spelling of 13000344002233 in words is "thirteen trillion, three hundred forty-four million, two thousand, two hundred thirty-three".