13000400301401 has 2 divisors, whose sum is σ = 13000400301402. Its totient is φ = 13000400301400.

The previous prime is 13000400301391. The next prime is 13000400301457. The reversal of 13000400301401 is 10410300400031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9484250281801 + 3516150019600 = 3079651^2 + 1875140^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13000400301401 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13000400301401.

It is not a weakly prime, because it can be changed into another prime (13000400301461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500200150700 + 6500200150701.

It is an arithmetic number, because the mean of its divisors is an integer number (6500200150701).

Almost surely, 2^{13000400301401} is an apocalyptic number.

It is an amenable number.

13000400301401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000400301401 is an equidigital number, since it uses as much as digits as its factorization.

13000400301401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13000400301401 its reverse (10410300400031), we get a palindrome (23410700701432).

The spelling of 13000400301401 in words is "thirteen trillion, four hundred million, three hundred one thousand, four hundred one".