13000424232 has 32 divisors (see below), whose sum is σ = 32512608000. Its totient is φ = 4331935104.

The previous prime is 13000424231. The next prime is 13000424243. The reversal of 13000424232 is 23242400031.

It is a super-2 number, since 2×13000424232² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13000424199 and 13000424208.

It is not an unprimeable number, because it can be changed into a prime (13000424231) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26232 + ... + 163367.

It is an arithmetic number, because the mean of its divisors is an integer number (1016019000).

Almost surely, 2^13000424232 is an apocalyptic number.

13000424232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13000424232 is an abundant number, since it is smaller than the sum of its proper divisors (19512183768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13000424232 is a wasteful number, since it uses less digits than its factorization.

13000424232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 192465 (or 192461 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 21.

Adding to 13000424232 its reverse (23242400031), we get a palindrome (36242824263).

The spelling of 13000424232 in words is "thirteen billion, four hundred twenty-four thousand, two hundred thirty-two".