Base | Representation |
---|---|
bin | 11000001101110001… |
… | …01110001011100111 |
3 | 1020120000121111100122 |
4 | 30012320232023213 |
5 | 203111102400112 |
6 | 5550004232155 |
7 | 640106604062 |
oct | 140670561347 |
9 | 36500544318 |
10 | 13000434407 |
11 | 5571451874 |
12 | 262999b65b |
13 | 12c24c464c |
14 | 8b483d8d9 |
15 | 5114da872 |
hex | 306e2e2e7 |
13000434407 has 2 divisors, whose sum is σ = 13000434408. Its totient is φ = 13000434406.
The previous prime is 13000434401. The next prime is 13000434427. The reversal of 13000434407 is 70443400031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13000434407 - 224 = 12983657191 is a prime.
It is a super-2 number, since 2×130004344072 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13000434401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500217203 + 6500217204.
It is an arithmetic number, because the mean of its divisors is an integer number (6500217204).
Almost surely, 213000434407 is an apocalyptic number.
13000434407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13000434407 is an equidigital number, since it uses as much as digits as its factorization.
13000434407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 26.
Adding to 13000434407 its reverse (70443400031), we get a palindrome (83443834438).
The spelling of 13000434407 in words is "thirteen billion, four hundred thirty-four thousand, four hundred seven".
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