130004421000000 has 784 divisors, whose sum is σ = 455833995250176. Its totient is φ = 32641920000000.

The previous prime is 130004420999911. The next prime is 130004421000019. The reversal of 130004421000000 is 124400031.

It is a super-2 number, since 2×130004421000000² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 3440981110 + ... + 3441018890.

Almost surely, 2^{130004421000000} is an apocalyptic number.

130004421000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130004421000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (227916997625088).

130004421000000 is an abundant number, since it is smaller than the sum of its proper divisors (325829574250176).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130004421000000 is an frugal number, since it uses more digits than its factorization.

130004421000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37894 (or 37859 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 130004421000000 its reverse (124400031), we get a palindrome (130004545400031).

The spelling of 130004421000000 in words is "one hundred thirty trillion, four billion, four hundred twenty-one million", and thus it is an aban number.