Base | Representation |
---|---|
bin | 11000001101110001… |
… | …11001101101100111 |
3 | 1020120000200220010222 |
4 | 30012320321231213 |
5 | 203111110403024 |
6 | 5550005234555 |
7 | 640110161555 |
oct | 140670715547 |
9 | 36500626128 |
10 | 13000481639 |
11 | 5571484302 |
12 | 2629a02a5b |
13 | 12c250ccb2 |
14 | 8b4852bd5 |
15 | 5114e985e |
hex | 306e39b67 |
13000481639 has 2 divisors, whose sum is σ = 13000481640. Its totient is φ = 13000481638.
The previous prime is 13000481629. The next prime is 13000481677. The reversal of 13000481639 is 93618400031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13000481639 - 24 = 13000481623 is a prime.
It is a super-2 number, since 2×130004816392 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 13000481599 and 13000481608.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13000481629) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500240819 + 6500240820.
It is an arithmetic number, because the mean of its divisors is an integer number (6500240820).
Almost surely, 213000481639 is an apocalyptic number.
13000481639 is a deficient number, since it is larger than the sum of its proper divisors (1).
13000481639 is an equidigital number, since it uses as much as digits as its factorization.
13000481639 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 13000481639 in words is "thirteen billion, four hundred eighty-one thousand, six hundred thirty-nine".
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