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13000481639 is a prime number
BaseRepresentation
bin11000001101110001…
…11001101101100111
31020120000200220010222
430012320321231213
5203111110403024
65550005234555
7640110161555
oct140670715547
936500626128
1013000481639
115571484302
122629a02a5b
1312c250ccb2
148b4852bd5
155114e985e
hex306e39b67

13000481639 has 2 divisors, whose sum is σ = 13000481640. Its totient is φ = 13000481638.

The previous prime is 13000481629. The next prime is 13000481677. The reversal of 13000481639 is 93618400031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13000481639 - 24 = 13000481623 is a prime.

It is a super-2 number, since 2×130004816392 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 13000481599 and 13000481608.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000481629) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500240819 + 6500240820.

It is an arithmetic number, because the mean of its divisors is an integer number (6500240820).

Almost surely, 213000481639 is an apocalyptic number.

13000481639 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000481639 is an equidigital number, since it uses as much as digits as its factorization.

13000481639 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 13000481639 in words is "thirteen billion, four hundred eighty-one thousand, six hundred thirty-nine".