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130005220354041 = 343335073451347
BaseRepresentation
bin11101100011110100110010…
…111110100110011111111001
3122001022101012100000202020210
4131203310302332212133321
5114020001142402312131
61140255323532141333
736245365361035524
oct3543646276463771
9561271170022223
10130005220354041
11384729a472a50a
12126b7a71307849
135770593c76686
14241640161dbbb
151006b02a2a146
hex763d32fa67f9

130005220354041 has 4 divisors (see below), whose sum is σ = 173340293805392. Its totient is φ = 86670146902692.

The previous prime is 130005220354001. The next prime is 130005220354171. The reversal of 130005220354041 is 140453022500031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 130005220354041 - 210 = 130005220353017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130005220354001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21667536725671 + ... + 21667536725676.

It is an arithmetic number, because the mean of its divisors is an integer number (43335073451348).

Almost surely, 2130005220354041 is an apocalyptic number.

It is an amenable number.

130005220354041 is a deficient number, since it is larger than the sum of its proper divisors (43335073451351).

130005220354041 is an equidigital number, since it uses as much as digits as its factorization.

130005220354041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43335073451350.

The product of its (nonzero) digits is 14400, while the sum is 30.

Adding to 130005220354041 its reverse (140453022500031), we get a palindrome (270458242854072).

The spelling of 130005220354041 in words is "one hundred thirty trillion, five billion, two hundred twenty million, three hundred fifty-four thousand, forty-one".

Divisors: 1 3 43335073451347 130005220354041