Base | Representation |
---|---|
bin | 10010111010110001100… |
… | …111010101000110001101 |
3 | 11121021200102020210122120 |
4 | 102322301213111012031 |
5 | 132300010330010103 |
6 | 2433123405403153 |
7 | 162632461450401 |
oct | 22726147250615 |
9 | 4537612223576 |
10 | 1300060000653 |
11 | 461396a83607 |
12 | 18bb635694b9 |
13 | 9579767479b |
14 | 46ccd527101 |
15 | 23c3e328253 |
hex | 12eb19d518d |
1300060000653 has 4 divisors (see below), whose sum is σ = 1733413334208. Its totient is φ = 866706667100.
The previous prime is 1300060000649. The next prime is 1300060000661. The reversal of 1300060000653 is 3560000600031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1300060000653 - 22 = 1300060000649 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300060000663) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216676666773 + ... + 216676666778.
It is an arithmetic number, because the mean of its divisors is an integer number (433353333552).
Almost surely, 21300060000653 is an apocalyptic number.
It is an amenable number.
1300060000653 is a deficient number, since it is larger than the sum of its proper divisors (433353333555).
1300060000653 is an equidigital number, since it uses as much as digits as its factorization.
1300060000653 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 433353333554.
The product of its (nonzero) digits is 1620, while the sum is 24.
Adding to 1300060000653 its reverse (3560000600031), we get a palindrome (4860060600684).
The spelling of 1300060000653 in words is "one trillion, three hundred billion, sixty million, six hundred fifty-three", and thus it is an aban number.
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