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1300066311697 is a prime number
BaseRepresentation
bin10010111010110001111…
…111011001111000010001
311121021200212010102202221
4102322301333121320101
5132300013433433242
62433124152541041
7162632566214056
oct22726177317021
94537625112687
101300066311697
1146139a5a414a
1218bb656b1781
1395798a7422a
1446cd02cb02d
1523c3eb73167
hex12eb1fd9e11

1300066311697 has 2 divisors, whose sum is σ = 1300066311698. Its totient is φ = 1300066311696.

The previous prime is 1300066311587. The next prime is 1300066311743. The reversal of 1300066311697 is 7961136600031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1273954660416 + 26111651281 = 1128696^2 + 161591^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300066311697 - 211 = 1300066309649 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300066341697) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650033155848 + 650033155849.

It is an arithmetic number, because the mean of its divisors is an integer number (650033155849).

Almost surely, 21300066311697 is an apocalyptic number.

It is an amenable number.

1300066311697 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300066311697 is an equidigital number, since it uses as much as digits as its factorization.

1300066311697 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 122472, while the sum is 43.

The spelling of 1300066311697 in words is "one trillion, three hundred billion, sixty-six million, three hundred eleven thousand, six hundred ninety-seven".