Search a number
-
+
13000959721381 is a prime number
BaseRepresentation
bin1011110100110000010110…
…0101011111111110100101
31201000212202020101102111211
42331030011211133332211
53201001431142041011
643352320342431421
72511200621164042
oct275140545377645
951025666342454
1013000959721381
114162748912665
12155b80b132571
13733ca6761ca8
1432d36d68a1c9
151782b8a5db21
hexbd30595ffa5

13000959721381 has 2 divisors, whose sum is σ = 13000959721382. Its totient is φ = 13000959721380.

The previous prime is 13000959721223. The next prime is 13000959721391. The reversal of 13000959721381 is 18312795900031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9876783280225 + 3124176441156 = 3142735^2 + 1767534^2 .

It is an emirp because it is prime and its reverse (18312795900031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13000959721381 - 223 = 13000951332773 is a prime.

It is a super-2 number, since 2×130009597213812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000959721391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500479860690 + 6500479860691.

It is an arithmetic number, because the mean of its divisors is an integer number (6500479860691).

Almost surely, 213000959721381 is an apocalyptic number.

It is an amenable number.

13000959721381 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000959721381 is an equidigital number, since it uses as much as digits as its factorization.

13000959721381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 408240, while the sum is 49.

The spelling of 13000959721381 in words is "thirteen trillion, nine hundred fifty-nine million, seven hundred twenty-one thousand, three hundred eighty-one".