Base | Representation |
---|---|
bin | 11000001101110101… |
… | …11000100100000110 |
3 | 1020120001200021212210 |
4 | 30012322320210012 |
5 | 203111224014342 |
6 | 5550024324250 |
7 | 640114454436 |
oct | 140672704406 |
9 | 36501607783 |
10 | 13001001222 |
11 | 55717a9710 |
12 | 262a013686 |
13 | 12c2662641 |
14 | 8b494a2c6 |
15 | 51159d79c |
hex | 306eb8906 |
13001001222 has 16 divisors (see below), whose sum is σ = 28365820992. Its totient is φ = 3939697320.
The previous prime is 13001001193. The next prime is 13001001257. The reversal of 13001001222 is 22210010031.
It is a junction number, because it is equal to n+sod(n) for n = 13001001198 and 13001001207.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 98492368 + ... + 98492499.
It is an arithmetic number, because the mean of its divisors is an integer number (1772863812).
Almost surely, 213001001222 is an apocalyptic number.
13001001222 is an abundant number, since it is smaller than the sum of its proper divisors (15364819770).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13001001222 is a wasteful number, since it uses less digits than its factorization.
13001001222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 196984883.
The product of its (nonzero) digits is 24, while the sum is 12.
Adding to 13001001222 its reverse (22210010031), we get a palindrome (35211011253).
The spelling of 13001001222 in words is "thirteen billion, one million, one thousand, two hundred twenty-two".
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