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1300100130314 = 25312265095569
BaseRepresentation
bin10010111010110100000…
…000011010011000001010
311121021210012202121012022
4102322310000122120022
5132300101113132224
62433131401444442
7162633456525446
oct22726400323012
94537705677168
101300100130314
114614076a2617
1218bb74aa0722
13957a2a8534b
1446cd49b1826
1523c42b0365e
hex12eb401a60a

1300100130314 has 8 divisors (see below), whose sum is σ = 1986945482340. Its totient is φ = 637784969536.

The previous prime is 1300100130257. The next prime is 1300100130317. The reversal of 1300100130314 is 4130310010031.

It can be written as a sum of positive squares in 2 ways, for example, as 1206932946025 + 93167184289 = 1098605^2 + 305233^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1300100130292 and 1300100130301.

It is not an unprimeable number, because it can be changed into a prime (1300100130317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6132547679 + ... + 6132547890.

Almost surely, 21300100130314 is an apocalyptic number.

1300100130314 is a deficient number, since it is larger than the sum of its proper divisors (686845352026).

1300100130314 is a wasteful number, since it uses less digits than its factorization.

1300100130314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12265095624.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1300100130314 its reverse (4130310010031), we get a palindrome (5430410140345).

The spelling of 1300100130314 in words is "one trillion, three hundred billion, one hundred million, one hundred thirty thousand, three hundred fourteen".

Divisors: 1 2 53 106 12265095569 24530191138 650050065157 1300100130314