Base | Representation |
---|---|
bin | 11101100011111001010110… |
… | …011111110100000010110010 |
3 | 122001022211211012001222221122 |
4 | 131203321112133310002302 |
5 | 114020041201433331010 |
6 | 1140301453124422242 |
7 | 36245630516560505 |
oct | 3543712637640262 |
9 | 561284735058848 |
10 | 130010111230130 |
11 | 38474a8448406a |
12 | 126b89b7247982 |
13 | 5770b933188b1 |
14 | 2416746dd713c |
15 | 1006cdc0c8855 |
hex | 763e567f40b2 |
130010111230130 has 32 divisors (see below), whose sum is σ = 237635063079984. Its totient is φ = 51202766462976.
The previous prime is 130010111230099. The next prime is 130010111230177. The reversal of 130010111230130 is 31032111010031.
It can be written as a sum of positive squares in 8 ways, for example, as 123919487039569 + 6090624190561 = 11131913^2 + 2467919^2 .
It is a junction number, because it is equal to n+sod(n) for n = 130010111230099 and 130010111230108.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 153908117 + ... + 154750536.
Almost surely, 2130010111230130 is an apocalyptic number.
130010111230130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130010111230130 is a deficient number, since it is larger than the sum of its proper divisors (107624951849854).
130010111230130 is a wasteful number, since it uses less digits than its factorization.
130010111230130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 308659310.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 130010111230130 its reverse (31032111010031), we get a palindrome (161042222240161).
The spelling of 130010111230130 in words is "one hundred thirty trillion, ten billion, one hundred eleven million, two hundred thirty thousand, one hundred thirty".
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