1300101133231 has 2 divisors, whose sum is σ = 1300101133232. Its totient is φ = 1300101133230.

The previous prime is 1300101133213. The next prime is 1300101133259. The reversal of 1300101133231 is 1323311010031.

Together with previous prime (1300101133213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1300101133231 - 2¹⁷ = 1300101002159 is a prime.

It is a super-2 number, since 2×1300101133231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300101133199 and 1300101133208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300101133831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650050566615 + 650050566616.

It is an arithmetic number, because the mean of its divisors is an integer number (650050566616).

Almost surely, 2^{1300101133231} is an apocalyptic number.

1300101133231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300101133231 is an equidigital number, since it uses as much as digits as its factorization.

1300101133231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1300101133231 its reverse (1323311010031), we get a palindrome (2623412143262).

The spelling of 1300101133231 in words is "one trillion, three hundred billion, one hundred one million, one hundred thirty-three thousand, two hundred thirty-one".