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13001021003 = 13217983659
BaseRepresentation
bin11000001101110101…
…11101011001001011
31020120001201022000102
430012322331121023
5203111230133003
65550025000015
7640114566215
oct140672753113
936501638012
1013001021003
115571812563
12262a02300b
1312c266b649
148b49535b5
155115a4588
hex306ebd64b

13001021003 has 4 divisors (see below), whose sum is σ = 13002017880. Its totient is φ = 13000024128.

The previous prime is 13001020973. The next prime is 13001021021. The reversal of 13001021003 is 30012010031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30012010031 = 222591348309.

It is a cyclic number.

It is not a de Polignac number, because 13001021003 - 26 = 13001020939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13001021023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 478613 + ... + 505046.

It is an arithmetic number, because the mean of its divisors is an integer number (3250504470).

Almost surely, 213001021003 is an apocalyptic number.

13001021003 is a deficient number, since it is larger than the sum of its proper divisors (996877).

13001021003 is an equidigital number, since it uses as much as digits as its factorization.

13001021003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 996876.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 13001021003 its reverse (30012010031), we get a palindrome (43013031034).

The spelling of 13001021003 in words is "thirteen billion, one million, twenty-one thousand, three".

Divisors: 1 13217 983659 13001021003