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130010221232981 is a prime number
BaseRepresentation
bin11101100011111001011101…
…000011011100001101010101
3122001022212002212001201111022
4131203321131003130031111
5114020041413113423411
61140301512054250525
736245633323563515
oct3543713503341525
9561285085051438
10130010221232981
1138475030587911
12126b8a28056a45
135770bb005233b
14241675786d845
151006ce6aa6edb
hex763e5d0dc355

130010221232981 has 2 divisors, whose sum is σ = 130010221232982. Its totient is φ = 130010221232980.

The previous prime is 130010221232917. The next prime is 130010221233019. The reversal of 130010221232981 is 189232122010031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128913111628081 + 1097109604900 = 11353991^2 + 1047430^2 .

It is a cyclic number.

It is not a de Polignac number, because 130010221232981 - 26 = 130010221232917 is a prime.

It is a super-2 number, since 2×1300102212329812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130013221232981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005110616490 + 65005110616491.

It is an arithmetic number, because the mean of its divisors is an integer number (65005110616491).

Almost surely, 2130010221232981 is an apocalyptic number.

It is an amenable number.

130010221232981 is a deficient number, since it is larger than the sum of its proper divisors (1).

130010221232981 is an equidigital number, since it uses as much as digits as its factorization.

130010221232981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 35.

The spelling of 130010221232981 in words is "one hundred thirty trillion, ten billion, two hundred twenty-one million, two hundred thirty-two thousand, nine hundred eighty-one".