130010221233001 has 4 divisors (see below), whose sum is σ = 130403001357904. Its totient is φ = 129617441108100.

The previous prime is 130010221232981. The next prime is 130010221233019. The reversal of 130010221233001 is 100332122010031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130010221233001 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130010221233001.

It is not an unprimeable number, because it can be changed into a prime (130010221233071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196390061955 + ... + 196390062616.

It is an arithmetic number, because the mean of its divisors is an integer number (32600750339476).

Almost surely, 2^{130010221233001} is an apocalyptic number.

It is an amenable number.

130010221233001 is a deficient number, since it is larger than the sum of its proper divisors (392780124903).

130010221233001 is an equidigital number, since it uses as much as digits as its factorization.

130010221233001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 392780124902.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 130010221233001 its reverse (100332122010031), we get a palindrome (230342343243032).

The spelling of 130010221233001 in words is "one hundred thirty trillion, ten billion, two hundred twenty-one million, two hundred thirty-three thousand, one".