Base | Representation |
---|---|
bin | 11101100011111001011101… |
… | …000011011100001111001111 |
3 | 122001022212002212001201122211 |
4 | 131203321131003130033033 |
5 | 114020041413113424403 |
6 | 1140301512054251251 |
7 | 36245633323564051 |
oct | 3543713503341717 |
9 | 561285085051584 |
10 | 130010221233103 |
11 | 38475030587a12 |
12 | 126b8a28056b27 |
13 | 5770bb0052403 |
14 | 241675786d8d1 |
15 | 1006ce6aa706d |
hex | 763e5d0dc3cf |
130010221233103 has 2 divisors, whose sum is σ = 130010221233104. Its totient is φ = 130010221233102.
The previous prime is 130010221233071. The next prime is 130010221233169. The reversal of 130010221233103 is 301332122010031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130010221233103 - 25 = 130010221233071 is a prime.
It is a super-2 number, since 2×1300102212331032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130010228233103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005110616551 + 65005110616552.
It is an arithmetic number, because the mean of its divisors is an integer number (65005110616552).
Almost surely, 2130010221233103 is an apocalyptic number.
130010221233103 is a deficient number, since it is larger than the sum of its proper divisors (1).
130010221233103 is an equidigital number, since it uses as much as digits as its factorization.
130010221233103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 130010221233103 its reverse (301332122010031), we get a palindrome (431342343243134).
The spelling of 130010221233103 in words is "one hundred thirty trillion, ten billion, two hundred twenty-one million, two hundred thirty-three thousand, one hundred three".
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