130010242142141 has 4 divisors (see below), whose sum is σ = 130031586794784. Its totient is φ = 129988897489500.

The previous prime is 130010242142093. The next prime is 130010242142189. The reversal of 130010242142141 is 141241242010031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (130010242142093) and next prime (130010242142189).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130010242142141 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130010242142141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130010242142441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10672317185 + ... + 10672329366.

It is an arithmetic number, because the mean of its divisors is an integer number (32507896698696).

Almost surely, 2^{130010242142141} is an apocalyptic number.

It is an amenable number.

130010242142141 is a deficient number, since it is larger than the sum of its proper divisors (21344652643).

130010242142141 is an equidigital number, since it uses as much as digits as its factorization.

130010242142141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21344652642.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 130010242142141 its reverse (141241242010031), we get a palindrome (271251484152172).

The spelling of 130010242142141 in words is "one hundred thirty trillion, ten billion, two hundred forty-two million, one hundred forty-two thousand, one hundred forty-one".