13001040002401 has 8 divisors (see below), whose sum is σ = 14291219546208. Its totient is φ = 11728904928000.

The previous prime is 13001040002393. The next prime is 13001040002411. The reversal of 13001040002401 is 10420004010031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13001040002401 - 2³ = 13001040002393 is a prime.

It is a super-2 number, since 2×13001040002401² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13001040002411) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4511115840 + ... + 4511118721.

It is an arithmetic number, because the mean of its divisors is an integer number (1786402443276).

Almost surely, 2^{13001040002401} is an apocalyptic number.

13001040002401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13001040002401 is a deficient number, since it is larger than the sum of its proper divisors (1290179543807).

13001040002401 is a wasteful number, since it uses less digits than its factorization.

13001040002401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9022234703.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 13001040002401 its reverse (10420004010031), we get a palindrome (23421044012432).

The spelling of 13001040002401 in words is "thirteen trillion, one billion, forty million, two thousand, four hundred one".