1300110013019 has 2 divisors, whose sum is σ = 1300110013020. Its totient is φ = 1300110013018.

The previous prime is 1300110013001. The next prime is 1300110013021. The reversal of 1300110013019 is 9103100110031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300110013019 is a prime.

It is a super-2 number, since 2×1300110013019² (a number of 25 digits) contains 22 as substring.

Together with 1300110013021, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1300110013099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650055006509 + 650055006510.

It is an arithmetic number, because the mean of its divisors is an integer number (650055006510).

Almost surely, 2^{1300110013019} is an apocalyptic number.

1300110013019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300110013019 is an equidigital number, since it uses as much as digits as its factorization.

1300110013019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 20.

The spelling of 1300110013019 in words is "one trillion, three hundred billion, one hundred ten million, thirteen thousand, nineteen".