Base | Representation |
---|---|
bin | 11101100011111010001101… |
… | …110111101010111010001001 |
3 | 122001022221012221011010122002 |
4 | 131203322031313222322021 |
5 | 114020100102244343144 |
6 | 1140302125232240345 |
7 | 36245662530134135 |
oct | 3543721567527211 |
9 | 561287187133562 |
10 | 130011040231049 |
11 | 3847541091421a |
12 | 126b90163a00b5 |
13 | 5770cb0927593 |
14 | 24167d45423c5 |
15 | 1006d4393314e |
hex | 763e8ddeae89 |
130011040231049 has 2 divisors, whose sum is σ = 130011040231050. Its totient is φ = 130011040231048.
The previous prime is 130011040231021. The next prime is 130011040231099. The reversal of 130011040231049 is 940132040110031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 66716795761225 + 63294244469824 = 8168035^2 + 7955768^2 .
It is an emirp because it is prime and its reverse (940132040110031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130011040231049 - 28 = 130011040230793 is a prime.
It is not a weakly prime, because it can be changed into another prime (130011040231099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005520115524 + 65005520115525.
It is an arithmetic number, because the mean of its divisors is an integer number (65005520115525).
Almost surely, 2130011040231049 is an apocalyptic number.
It is an amenable number.
130011040231049 is a deficient number, since it is larger than the sum of its proper divisors (1).
130011040231049 is an equidigital number, since it uses as much as digits as its factorization.
130011040231049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
The spelling of 130011040231049 in words is "one hundred thirty trillion, eleven billion, forty million, two hundred thirty-one thousand, forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •