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130011103121 = 592203578019
BaseRepresentation
bin111100100010101000…
…0111111111110010001
3110102120200211100020112
41321011100333332101
54112230320244441
6135420513051105
712251540066654
oct1710520777621
9412520740215
10130011103121
1150156973069
1221244556a95
13c34c291523
146414b5989b
1535add084eb
hex1e4543ff91

130011103121 has 4 divisors (see below), whose sum is σ = 132214681200. Its totient is φ = 127807525044.

The previous prime is 130011103109. The next prime is 130011103153. The reversal of 130011103121 is 121301110031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130011103121 - 210 = 130011102097 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 130011103096 and 130011103105.

It is not an unprimeable number, because it can be changed into a prime (130011103421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1101788951 + ... + 1101789068.

It is an arithmetic number, because the mean of its divisors is an integer number (33053670300).

Almost surely, 2130011103121 is an apocalyptic number.

It is an amenable number.

130011103121 is a deficient number, since it is larger than the sum of its proper divisors (2203578079).

130011103121 is an equidigital number, since it uses as much as digits as its factorization.

130011103121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2203578078.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 130011103121 its reverse (121301110031), we get a palindrome (251312213152).

The spelling of 130011103121 in words is "one hundred thirty billion, eleven million, one hundred three thousand, one hundred twenty-one".

Divisors: 1 59 2203578019 130011103121