Base | Representation |
---|---|
bin | 111100100010101000… |
… | …1000100011000011101 |
3 | 110102120200212021000102 |
4 | 1321011101010120131 |
5 | 4112230321334211 |
6 | 135420513310445 |
7 | 12251540203424 |
oct | 1710521043035 |
9 | 412520767012 |
10 | 130011121181 |
11 | 50156985697 |
12 | 21244565425 |
13 | c34c299806 |
14 | 6414b622bb |
15 | 35add0da3b |
hex | 1e4544461d |
130011121181 has 2 divisors, whose sum is σ = 130011121182. Its totient is φ = 130011121180.
The previous prime is 130011121139. The next prime is 130011121213. The reversal of 130011121181 is 181121110031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 107131836100 + 22879285081 = 327310^2 + 151259^2 .
It is a cyclic number.
It is not a de Polignac number, because 130011121181 - 26 = 130011121117 is a prime.
It is a super-2 number, since 2×1300111211812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130011121481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005560590 + 65005560591.
It is an arithmetic number, because the mean of its divisors is an integer number (65005560591).
Almost surely, 2130011121181 is an apocalyptic number.
It is an amenable number.
130011121181 is a deficient number, since it is larger than the sum of its proper divisors (1).
130011121181 is an equidigital number, since it uses as much as digits as its factorization.
130011121181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 20.
The spelling of 130011121181 in words is "one hundred thirty billion, eleven million, one hundred twenty-one thousand, one hundred eighty-one".
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