Search a number
-
+
130011202323232 = 255483740990347
BaseRepresentation
bin11101100011111010010111…
…100010000000001100100000
3122001022221122020011021022021
4131203322113202000030200
5114020100420243320412
61140302153302351224
736245666535656116
oct3543722742001440
9561287566137267
10130011202323232
11384754943654aa
12126b906072b514
13577100839b409
14241680bc97ab6
151006d52ca0607
hex763e97880320

130011202323232 has 24 divisors (see below), whose sum is σ = 256006237311216. Its totient is φ = 64993745228352.

The previous prime is 130011202323221. The next prime is 130011202323361. The reversal of 130011202323232 is 232323202110031.

It is a junction number, because it is equal to n+sod(n) for n = 130011202323197 and 130011202323206.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 370319718 + ... + 370670629.

It is an arithmetic number, because the mean of its divisors is an integer number (10666926554634).

Almost surely, 2130011202323232 is an apocalyptic number.

It is an amenable number.

130011202323232 is a deficient number, since it is larger than the sum of its proper divisors (125995034987984).

130011202323232 is an equidigital number, since it uses as much as digits as its factorization.

130011202323232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 740995840 (or 740995832 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 130011202323232 its reverse (232323202110031), we get a palindrome (362334404433263).

The spelling of 130011202323232 in words is "one hundred thirty trillion, eleven billion, two hundred two million, three hundred twenty-three thousand, two hundred thirty-two".

Divisors: 1 2 4 8 16 32 5483 10966 21932 43864 87728 175456 740990347 1481980694 2963961388 5927922776 11855845552 23711691104 4062850072601 8125700145202 16251400290404 32502800580808 65005601161616 130011202323232