130011204493 has 2 divisors, whose sum is σ = 130011204494. Its totient is φ = 130011204492.

The previous prime is 130011204377. The next prime is 130011204503. The reversal of 130011204493 is 394402110031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127639709289 + 2371495204 = 357267^2 + 48698^2 .

It is an emirp because it is prime and its reverse (394402110031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130011204493 - 2¹⁷ = 130011073421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130011208493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005602246 + 65005602247.

It is an arithmetic number, because the mean of its divisors is an integer number (65005602247).

Almost surely, 2^130011204493 is an apocalyptic number.

It is an amenable number.

130011204493 is a deficient number, since it is larger than the sum of its proper divisors (1).

130011204493 is an equidigital number, since it uses as much as digits as its factorization.

130011204493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 130011204493 in words is "one hundred thirty billion, eleven million, two hundred four thousand, four hundred ninety-three".