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13001121311011 = 23565266143957
BaseRepresentation
bin1011110100110000111100…
…1101111010100100100011
31201000220011111110000210221
42331030033031322210203
53201002244023423021
643352344354103511
72511204622523611
oct275141715724443
951026144400727
1013001121311011
114162821050309
12155b85527ab97
1373400108b162
1432d386d106b1
151782c7d2c241
hexbd30f37a923

13001121311011 has 4 divisors (see below), whose sum is σ = 13566387454992. Its totient is φ = 12435855167032.

The previous prime is 13001121310981. The next prime is 13001121311051. The reversal of 13001121311011 is 11011312110031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13001121311011 - 217 = 13001121179939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13001121311051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 282633071956 + ... + 282633072001.

It is an arithmetic number, because the mean of its divisors is an integer number (3391596863748).

Almost surely, 213001121311011 is an apocalyptic number.

13001121311011 is a deficient number, since it is larger than the sum of its proper divisors (565266143981).

13001121311011 is an equidigital number, since it uses as much as digits as its factorization.

13001121311011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 565266143980.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 13001121311011 its reverse (11011312110031), we get a palindrome (24012433421042).

The spelling of 13001121311011 in words is "thirteen trillion, one billion, one hundred twenty-one million, three hundred eleven thousand, eleven".

Divisors: 1 23 565266143957 13001121311011