Base | Representation |
---|---|
bin | 111100100010101000… |
… | …1011100100001010001 |
3 | 110102120201001021122012 |
4 | 1321011101130201101 |
5 | 4112230333020144 |
6 | 135420515352305 |
7 | 12251541064604 |
oct | 1710521344121 |
9 | 412521037565 |
10 | 130011220049 |
11 | 50156a429a7 |
12 | 212445b2695 |
13 | c34c302809 |
14 | 6414b8a33b |
15 | 35add2ce9e |
hex | 1e4545c851 |
130011220049 has 2 divisors, whose sum is σ = 130011220050. Its totient is φ = 130011220048.
The previous prime is 130011219977. The next prime is 130011220069. The reversal of 130011220049 is 940022110031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 65257257025 + 64753963024 = 255455^2 + 254468^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130011220049 is a prime.
It is a super-3 number, since 3×1300112200493 (a number of 34 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (130011220069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005610024 + 65005610025.
It is an arithmetic number, because the mean of its divisors is an integer number (65005610025).
Almost surely, 2130011220049 is an apocalyptic number.
It is an amenable number.
130011220049 is a deficient number, since it is larger than the sum of its proper divisors (1).
130011220049 is an equidigital number, since it uses as much as digits as its factorization.
130011220049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
The spelling of 130011220049 in words is "one hundred thirty billion, eleven million, two hundred twenty thousand, forty-nine".
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