13001123110249 has 2 divisors, whose sum is σ = 13001123110250. Its totient is φ = 13001123110248.

The previous prime is 13001123110247. The next prime is 13001123110273. The reversal of 13001123110249 is 94201132110031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12996695538649 + 4427571600 = 3605093^2 + 66540^2 .

It is an emirp because it is prime and its reverse (94201132110031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13001123110249 - 2¹ = 13001123110247 is a prime.

Together with 13001123110247, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13001123110247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500561555124 + 6500561555125.

It is an arithmetic number, because the mean of its divisors is an integer number (6500561555125).

Almost surely, 2^{13001123110249} is an apocalyptic number.

It is an amenable number.

13001123110249 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001123110249 is an equidigital number, since it uses as much as digits as its factorization.

13001123110249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 28.

The spelling of 13001123110249 in words is "thirteen trillion, one billion, one hundred twenty-three million, one hundred ten thousand, two hundred forty-nine".