Base | Representation |
---|---|
bin | 10010111010110100110… |
… | …001100111110010111011 |
3 | 11121021211010000222200201 |
4 | 102322310301213302323 |
5 | 132300112413432311 |
6 | 2433132542143031 |
7 | 162634004264023 |
oct | 22726461476273 |
9 | 4537733028621 |
10 | 1300113030331 |
11 | 461413a03595 |
12 | 18bb79281a77 |
13 | 957a5650bab |
14 | 46cd65aca83 |
15 | 23c43d009c1 |
hex | 12eb4c67cbb |
1300113030331 has 2 divisors, whose sum is σ = 1300113030332. Its totient is φ = 1300113030330.
The previous prime is 1300113030323. The next prime is 1300113030361. The reversal of 1300113030331 is 1330303110031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1300113030331 - 23 = 1300113030323 is a prime.
It is a super-2 number, since 2×13001130303312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1300113030299 and 1300113030308.
It is not a weakly prime, because it can be changed into another prime (1300113030361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650056515165 + 650056515166.
It is an arithmetic number, because the mean of its divisors is an integer number (650056515166).
Almost surely, 21300113030331 is an apocalyptic number.
1300113030331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300113030331 is an equidigital number, since it uses as much as digits as its factorization.
1300113030331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 19.
Adding to 1300113030331 its reverse (1330303110031), we get a palindrome (2630416140362).
The spelling of 1300113030331 in words is "one trillion, three hundred billion, one hundred thirteen million, thirty thousand, three hundred thirty-one".
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