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1300113030331 is a prime number
BaseRepresentation
bin10010111010110100110…
…001100111110010111011
311121021211010000222200201
4102322310301213302323
5132300112413432311
62433132542143031
7162634004264023
oct22726461476273
94537733028621
101300113030331
11461413a03595
1218bb79281a77
13957a5650bab
1446cd65aca83
1523c43d009c1
hex12eb4c67cbb

1300113030331 has 2 divisors, whose sum is σ = 1300113030332. Its totient is φ = 1300113030330.

The previous prime is 1300113030323. The next prime is 1300113030361. The reversal of 1300113030331 is 1330303110031.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1300113030331 - 23 = 1300113030323 is a prime.

It is a super-2 number, since 2×13001130303312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300113030299 and 1300113030308.

It is not a weakly prime, because it can be changed into another prime (1300113030361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650056515165 + 650056515166.

It is an arithmetic number, because the mean of its divisors is an integer number (650056515166).

Almost surely, 21300113030331 is an apocalyptic number.

1300113030331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300113030331 is an equidigital number, since it uses as much as digits as its factorization.

1300113030331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 19.

Adding to 1300113030331 its reverse (1330303110031), we get a palindrome (2630416140362).

The spelling of 1300113030331 in words is "one trillion, three hundred billion, one hundred thirteen million, thirty thousand, three hundred thirty-one".