130011410403141 has 4 divisors (see below), whose sum is σ = 173348547204192. Its totient is φ = 86674273602092.

The previous prime is 130011410403139. The next prime is 130011410403179. The reversal of 130011410403141 is 141304014110031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130011410403141 - 2¹ = 130011410403139 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130011410403241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21668568400521 + ... + 21668568400526.

It is an arithmetic number, because the mean of its divisors is an integer number (43337136801048).

Almost surely, 2^{130011410403141} is an apocalyptic number.

It is an amenable number.

130011410403141 is a deficient number, since it is larger than the sum of its proper divisors (43337136801051).

130011410403141 is an equidigital number, since it uses as much as digits as its factorization.

130011410403141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43337136801050.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 130011410403141 its reverse (141304014110031), we get a palindrome (271315424513172).

The spelling of 130011410403141 in words is "one hundred thirty trillion, eleven billion, four hundred ten million, four hundred three thousand, one hundred forty-one".