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130011420214 = 213107362312899
BaseRepresentation
bin111100100010101001…
…0001101011000110110
3110102120201102110012201
41321011102031120312
54112230410421324
6135420523535114
712251542560304
oct1710522153066
9412521373181
10130011420214
115015706a325
122124468a49a
13c34c372960
146414bdd274
1535add6c444
hex1e4548d636

130011420214 has 32 divisors (see below), whose sum is σ = 212056185600. Its totient is φ = 59423459232.

The previous prime is 130011420193. The next prime is 130011420223. The reversal of 130011420214 is 412024110031.

It is a super-2 number, since 2×1300114202142 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130011420191 and 130011420200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10072737 + ... + 10085635.

It is an arithmetic number, because the mean of its divisors is an integer number (6626755800).

Almost surely, 2130011420214 is an apocalyptic number.

130011420214 is a deficient number, since it is larger than the sum of its proper divisors (82044765386).

130011420214 is a wasteful number, since it uses less digits than its factorization.

130011420214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16644.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 130011420214 its reverse (412024110031), we get a palindrome (542035530245).

The spelling of 130011420214 in words is "one hundred thirty billion, eleven million, four hundred twenty thousand, two hundred fourteen".

Divisors: 1 2 13 26 107 214 1391 2782 3623 7246 12899 25798 47099 94198 167687 335374 387661 775322 1380193 2760386 5039593 10079186 17942509 35885018 46733077 93466154 607530001 1215060002 5000439239 10000878478 65005710107 130011420214