Base | Representation |
---|---|
bin | 111100100010101001… |
… | …0001101011000110110 |
3 | 110102120201102110012201 |
4 | 1321011102031120312 |
5 | 4112230410421324 |
6 | 135420523535114 |
7 | 12251542560304 |
oct | 1710522153066 |
9 | 412521373181 |
10 | 130011420214 |
11 | 5015706a325 |
12 | 2124468a49a |
13 | c34c372960 |
14 | 6414bdd274 |
15 | 35add6c444 |
hex | 1e4548d636 |
130011420214 has 32 divisors (see below), whose sum is σ = 212056185600. Its totient is φ = 59423459232.
The previous prime is 130011420193. The next prime is 130011420223. The reversal of 130011420214 is 412024110031.
It is a super-2 number, since 2×1300114202142 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130011420191 and 130011420200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10072737 + ... + 10085635.
It is an arithmetic number, because the mean of its divisors is an integer number (6626755800).
Almost surely, 2130011420214 is an apocalyptic number.
130011420214 is a deficient number, since it is larger than the sum of its proper divisors (82044765386).
130011420214 is a wasteful number, since it uses less digits than its factorization.
130011420214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16644.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 130011420214 its reverse (412024110031), we get a palindrome (542035530245).
The spelling of 130011420214 in words is "one hundred thirty billion, eleven million, four hundred twenty thousand, two hundred fourteen".
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