Base | Representation |
---|---|
bin | 11101100011111011001000… |
… | …010101000001000000100101 |
3 | 122001100000202021122110211101 |
4 | 131203323020111001000211 |
5 | 114020104104334033102 |
6 | 1140302410425440101 |
7 | 36246026036430361 |
oct | 3543731025010045 |
9 | 561300667573741 |
10 | 130012021002277 |
11 | 384758744a4157 |
12 | 126b924a940031 |
13 | 5771108b9139b |
14 | 24168888c62a1 |
15 | 1006d9eab6e87 |
hex | 763ec8541025 |
130012021002277 has 2 divisors, whose sum is σ = 130012021002278. Its totient is φ = 130012021002276.
The previous prime is 130012021002229. The next prime is 130012021002299. The reversal of 130012021002277 is 772200120210031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92866969836001 + 37145051166276 = 9636751^2 + 6094674^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130012021002277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130012021002977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006010501138 + 65006010501139.
It is an arithmetic number, because the mean of its divisors is an integer number (65006010501139).
Almost surely, 2130012021002277 is an apocalyptic number.
It is an amenable number.
130012021002277 is a deficient number, since it is larger than the sum of its proper divisors (1).
130012021002277 is an equidigital number, since it uses as much as digits as its factorization.
130012021002277 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2352, while the sum is 28.
The spelling of 130012021002277 in words is "one hundred thirty trillion, twelve billion, twenty-one million, two thousand, two hundred seventy-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •