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130012021102231 = 196842737952749
BaseRepresentation
bin11101100011111011001000…
…010101011001011010010111
3122001100000202021211112221101
4131203323020111121122113
5114020104104400232411
61140302410431530531
736246026040324652
oct3543731025313227
9561300667745841
10130012021102231
1138475874562264
12126b924a989a47
135771108bc7a28
142416888910899
151006d9ead68c1
hex763ec8559697

130012021102231 has 4 divisors (see below), whose sum is σ = 136854759055000. Its totient is φ = 123169283149464.

The previous prime is 130012021102199. The next prime is 130012021102279. The reversal of 130012021102231 is 132201120210031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130012021102231 - 25 = 130012021102199 is a prime.

It is a super-2 number, since 2×1300120211022312 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 6842737952749 = 130012021102231 / (1 + 3 + 0 + 0 + 1 + 2 + 0 + 2 + 1 + 1 + 0 + 2 + 2 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130012021102199 and 130012021102208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130012021109231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3421368976356 + ... + 3421368976393.

It is an arithmetic number, because the mean of its divisors is an integer number (34213689763750).

Almost surely, 2130012021102231 is an apocalyptic number.

130012021102231 is a deficient number, since it is larger than the sum of its proper divisors (6842737952769).

130012021102231 is an equidigital number, since it uses as much as digits as its factorization.

130012021102231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6842737952768.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 130012021102231 its reverse (132201120210031), we get a palindrome (262213141312262).

The spelling of 130012021102231 in words is "one hundred thirty trillion, twelve billion, twenty-one million, one hundred two thousand, two hundred thirty-one".

Divisors: 1 19 6842737952749 130012021102231