Base | Representation |
---|---|
bin | 11101100011111011001001… |
… | …000010111100111000101011 |
3 | 122001100000210010022020222112 |
4 | 131203323021002330320223 |
5 | 114020104120424402021 |
6 | 1140302411535512535 |
7 | 36246026243662436 |
oct | 3543731102747053 |
9 | 561300703266875 |
10 | 130012033044011 |
11 | 384758802792a8 |
12 | 126b925298874b |
13 | 577110b519381 |
14 | 241688a33c81d |
15 | 1006da0b94d5b |
hex | 763ec90bce2b |
130012033044011 has 2 divisors, whose sum is σ = 130012033044012. Its totient is φ = 130012033044010.
The previous prime is 130012033043993. The next prime is 130012033044037. The reversal of 130012033044011 is 110440330210031.
It is a weak prime.
It is an emirp because it is prime and its reverse (110440330210031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130012033044011 - 218 = 130012032781867 is a prime.
It is not a weakly prime, because it can be changed into another prime (130012033049011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006016522005 + 65006016522006.
It is an arithmetic number, because the mean of its divisors is an integer number (65006016522006).
Almost surely, 2130012033044011 is an apocalyptic number.
130012033044011 is a deficient number, since it is larger than the sum of its proper divisors (1).
130012033044011 is an equidigital number, since it uses as much as digits as its factorization.
130012033044011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 130012033044011 its reverse (110440330210031), we get a palindrome (240452363254042).
The spelling of 130012033044011 in words is "one hundred thirty trillion, twelve billion, thirty-three million, forty-four thousand, eleven".
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