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130012033044011 is a prime number
BaseRepresentation
bin11101100011111011001001…
…000010111100111000101011
3122001100000210010022020222112
4131203323021002330320223
5114020104120424402021
61140302411535512535
736246026243662436
oct3543731102747053
9561300703266875
10130012033044011
11384758802792a8
12126b925298874b
13577110b519381
14241688a33c81d
151006da0b94d5b
hex763ec90bce2b

130012033044011 has 2 divisors, whose sum is σ = 130012033044012. Its totient is φ = 130012033044010.

The previous prime is 130012033043993. The next prime is 130012033044037. The reversal of 130012033044011 is 110440330210031.

It is a weak prime.

It is an emirp because it is prime and its reverse (110440330210031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130012033044011 - 218 = 130012032781867 is a prime.

It is not a weakly prime, because it can be changed into another prime (130012033049011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006016522005 + 65006016522006.

It is an arithmetic number, because the mean of its divisors is an integer number (65006016522006).

Almost surely, 2130012033044011 is an apocalyptic number.

130012033044011 is a deficient number, since it is larger than the sum of its proper divisors (1).

130012033044011 is an equidigital number, since it uses as much as digits as its factorization.

130012033044011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 130012033044011 its reverse (110440330210031), we get a palindrome (240452363254042).

The spelling of 130012033044011 in words is "one hundred thirty trillion, twelve billion, thirty-three million, forty-four thousand, eleven".