Search a number
-
+
1300121022041 is a prime number
BaseRepresentation
bin10010111010110101010…
…000000110111001011001
311121021211200002000020222
4102322311100012321121
5132300121440201131
62433133425325425
7162634132230332
oct22726520067131
94537750060228
101300121022041
11461418471906
1218bb7ba96875
13957a71bb60a
1446cd768d289
1523c4487d87b
hex12eb5406e59

1300121022041 has 2 divisors, whose sum is σ = 1300121022042. Its totient is φ = 1300121022040.

The previous prime is 1300121021993. The next prime is 1300121022073. The reversal of 1300121022041 is 1402201210031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 885050074441 + 415070947600 = 940771^2 + 644260^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300121022041 - 26 = 1300121021977 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1300121025041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650060511020 + 650060511021.

It is an arithmetic number, because the mean of its divisors is an integer number (650060511021).

Almost surely, 21300121022041 is an apocalyptic number.

It is an amenable number.

1300121022041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300121022041 is an equidigital number, since it uses as much as digits as its factorization.

1300121022041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1300121022041 its reverse (1402201210031), we get a palindrome (2702322232072).

The spelling of 1300121022041 in words is "one trillion, three hundred billion, one hundred twenty-one million, twenty-two thousand, forty-one".