Base | Representation |
---|---|
bin | 10010111010110101010… |
… | …000000110111001011001 |
3 | 11121021211200002000020222 |
4 | 102322311100012321121 |
5 | 132300121440201131 |
6 | 2433133425325425 |
7 | 162634132230332 |
oct | 22726520067131 |
9 | 4537750060228 |
10 | 1300121022041 |
11 | 461418471906 |
12 | 18bb7ba96875 |
13 | 957a71bb60a |
14 | 46cd768d289 |
15 | 23c4487d87b |
hex | 12eb5406e59 |
1300121022041 has 2 divisors, whose sum is σ = 1300121022042. Its totient is φ = 1300121022040.
The previous prime is 1300121021993. The next prime is 1300121022073. The reversal of 1300121022041 is 1402201210031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 885050074441 + 415070947600 = 940771^2 + 644260^2 .
It is a cyclic number.
It is not a de Polignac number, because 1300121022041 - 26 = 1300121021977 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1300121025041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650060511020 + 650060511021.
It is an arithmetic number, because the mean of its divisors is an integer number (650060511021).
Almost surely, 21300121022041 is an apocalyptic number.
It is an amenable number.
1300121022041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300121022041 is an equidigital number, since it uses as much as digits as its factorization.
1300121022041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 1300121022041 its reverse (1402201210031), we get a palindrome (2702322232072).
The spelling of 1300121022041 in words is "one trillion, three hundred billion, one hundred twenty-one million, twenty-two thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •