Base | Representation |
---|---|
bin | 11101100011111011010111… |
… | …100100101011111110100111 |
3 | 122001100001102002220202101002 |
4 | 131203323113210223332213 |
5 | 114020110120323044204 |
6 | 1140302452043423515 |
7 | 36246035263420124 |
oct | 3543732744537647 |
9 | 561301362822332 |
10 | 130012276768679 |
11 | 38475995906248 |
12 | 126b9300524b9b |
13 | 5771149b72656 |
14 | 24168b086374b |
15 | 1006db728991e |
hex | 763ed792bfa7 |
130012276768679 has 2 divisors, whose sum is σ = 130012276768680. Its totient is φ = 130012276768678.
The previous prime is 130012276768667. The next prime is 130012276768723. The reversal of 130012276768679 is 976867672210031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130012276768679 - 212 = 130012276764583 is a prime.
It is a super-2 number, since 2×1300122767686792 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130012276767679) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006138384339 + 65006138384340.
It is an arithmetic number, because the mean of its divisors is an integer number (65006138384340).
Almost surely, 2130012276768679 is an apocalyptic number.
130012276768679 is a deficient number, since it is larger than the sum of its proper divisors (1).
130012276768679 is an equidigital number, since it uses as much as digits as its factorization.
130012276768679 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64012032, while the sum is 65.
The spelling of 130012276768679 in words is "one hundred thirty trillion, twelve billion, two hundred seventy-six million, seven hundred sixty-eight thousand, six hundred seventy-nine".
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