Base | Representation |
---|---|
bin | 11101100011111011011001… |
… | …100011111010101101101011 |
3 | 122001100001111102200020121012 |
4 | 131203323121203322231223 |
5 | 114020110202342340243 |
6 | 1140302455234334135 |
7 | 36246036150051140 |
oct | 3543733143725553 |
9 | 561301442606535 |
10 | 130012310121323 |
11 | 38475a02716613 |
12 | 126b930b72a34b |
13 | 5771153a4c646 |
14 | 24168b50663c7 |
15 | 1006dba176d18 |
hex | 763ed98fab6b |
130012310121323 has 8 divisors (see below), whose sum is σ = 148586142270720. Its totient is φ = 111438639219240.
The previous prime is 130012310121247. The next prime is 130012310121401. The reversal of 130012310121323 is 323121013210031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130012310121323 - 230 = 130011236379499 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130012310121523) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38579093 + ... + 41813526.
It is an arithmetic number, because the mean of its divisors is an integer number (18573267783840).
Almost surely, 2130012310121323 is an apocalyptic number.
130012310121323 is a deficient number, since it is larger than the sum of its proper divisors (18573832149397).
130012310121323 is an equidigital number, since it uses as much as digits as its factorization.
130012310121323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80623657.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 130012310121323 its reverse (323121013210031), we get a palindrome (453133323331354).
The spelling of 130012310121323 in words is "one hundred thirty trillion, twelve billion, three hundred ten million, one hundred twenty-one thousand, three hundred twenty-three".
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