130013000133311 has 2 divisors, whose sum is σ = 130013000133312. Its totient is φ = 130013000133310.

The previous prime is 130013000133293. The next prime is 130013000133323. The reversal of 130013000133311 is 113331000310031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130013000133311 is a prime.

It is a super-2 number, since 2×130013000133311² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130013000133361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006500066655 + 65006500066656.

It is an arithmetic number, because the mean of its divisors is an integer number (65006500066656).

Almost surely, 2^{130013000133311} is an apocalyptic number.

130013000133311 is a deficient number, since it is larger than the sum of its proper divisors (1).

130013000133311 is an equidigital number, since it uses as much as digits as its factorization.

130013000133311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 130013000133311 its reverse (113331000310031), we get a palindrome (243344000443342).

The spelling of 130013000133311 in words is "one hundred thirty trillion, thirteen billion, one hundred thirty-three thousand, three hundred eleven".